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A watch showed a time of fourteen minutes past nine (9 hrs and 14 mins). The positions of the hour-hand and the minute-hand of the watch are exactly interchanged. The new time shown by the watch is closest to which one of the following?
Explanation
Use standard clock-angle relations: the hour hand moves 30° per hour (0.5° per minute) and the minute hand 6° per minute. At 9:14 the hour-hand angle = 30·9 + 0.5·14 = 277° and the minute-hand angle = 6·14 = 84°. After exact interchange the new minute-angle = 277°, so the minutes = 277/6 = 46.1667 minutes (46 minutes 10 seconds). The new hour-angle must be 84°, which corresponds to roughly 2 hours plus those minutes, so the new time ≈ 2:46:10 — i.e. about 14 minutes to 3. Hence option (3) Fourteen minutes to three is closest.
Detailed Concept Breakdown
9 concepts, approximately 18 minutes to master.
1. Clock Dial Geometry and Basic Divisions (basic)
To master clock problems, we must first view the clock dial through the lens of geometry. A standard clock is a circle, which contains 360°. This circle is divided into 12 equal major sectors by the numbers 1 to 12. Each major sector represents one hour and spans an angle of 30° (360° ÷ 12). Furthermore, each of these sectors is divided into five smaller intervals, making a total of 60 minute divisions across the whole dial. As noted in basic science, the standard units for these measurements are the hour (h) and the minute (min), always written in lowercase Science-Class VII, Measurement of Time and Motion, p.111. Understanding the relative speeds of the hands is the secret to solving complex questions. The minute hand is the faster traveler; it completes a full 360° rotation in 60 minutes. Therefore, its angular speed is 6° per minute (360° / 60 min). On the other hand, the hour hand is much slower. It takes 12 hours to cover the same 360°, moving at a rate of 30° per hour. Crucially, the hour hand doesn't stay still while the minute hand moves—it creeps forward at a rate of 0.5° per minute (30° / 60 min). This geometric division of time mirrors how we calculate longitudes on Earth. Just as the Earth rotates 360° in 24 hours—meaning it passes through 15° in one hour or 1° in 4 minutes—the clock dial simplifies this into a 12-hour cycle for our daily use Certificate Physical and Human Geography, The Earth's Crust, p.11. By keeping these two constants (6°/min for the minute hand and 0.5°/min for the hour hand) in your mind, you can calculate the exact position of any hand at any given moment.Sources: Science-Class VII, Measurement of Time and Motion, p.111; Certificate Physical and Human Geography, The Earth's Crust, p.11
2. Angular Speed of Clock Hands (basic)
To understand how clock hands move, we first look at the clock face as a perfect circle consisting of 360°. Speed, at its simplest, is the distance covered in a unit of time Science-Class VII . NCERT, Measurement of Time and Motion, p.113. In the case of a clock, we measure 'angular distance' in degrees rather than linear distance in kilometers. Just as the Earth rotates through 360° in 24 hours to determine local time Certificate Physical and Human Geography, GC Leong, The Earth's Crust, p.11, the hands of a clock rotate through the same 360° but at different fixed rates. Let's break down the Minute Hand first. This hand completes one full revolution (360°) every 60 minutes. Therefore, its angular speed is calculated as 360° ÷ 60 minutes, which equals 6° per minute. This means every time the 'second' hand completes a full lap, the minute hand nudges forward by exactly 6°. This is the faster-moving hand we use for precise timing in our daily observations Science-Class VII . NCERT, Measurement of Time and Motion, p.112. The Hour Hand moves much more slowly. It takes 12 hours to complete one full 360° circle. To find its hourly speed, we divide 360° by 12, giving us 30° per hour (which is the gap between any two consecutive numbers on a clock, like 12 to 1). To find its speed per minute, we divide that 30° by 60 minutes, resulting in a speed of 0.5° per minute. While it seems almost stationary, it is constantly crawling forward at this tiny rate.| Clock Hand | Full Rotation Time | Angular Speed (per min) | Angular Speed (per hour) |
|---|---|---|---|
| Minute Hand | 60 Minutes | 6° | 360° |
| Hour Hand | 12 Hours | 0.5° | 30° |
Sources: Science-Class VII . NCERT, Measurement of Time and Motion, p.112-113; Certificate Physical and Human Geography, GC Leong, The Earth's Crust, p.11
3. Relative Speed and Coincidence of Hands (intermediate)
To master clock problems, we must treat the clock face as a circular track where two "runners"—the hour hand and the minute hand—move at constant speeds. Historically, humans used varying methods to track these intervals, from shadow-based measurements in ancient India to the sinking bowl water clocks described in the Arthasastra Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.108. Today, we rely on the circular geometry of the clock, where a full rotation represents 360°.
The speed of each hand is derived from how much of the circle it covers over time:
- Minute Hand: Completes 360° in 60 minutes. Speed = 360 / 60 = 6° per minute.
- Hour Hand: Completes 360° in 12 hours (720 minutes). Speed = 360 / 720 = 0.5° per minute.
Because both hands move in the same clockwise direction, we calculate their relative speed by finding the difference between them. The minute hand "gains" on the hour hand at a rate of 5.5° per minute (6° - 0.5°). This relative speed is the engine behind all "coincidence" problems. For the hands to coincide (overlap), the minute hand must close the angular gap between them using this relative speed of 5.5°/min. While early pendulum clocks might lose 10 seconds a day, our mathematical models assume a perfect, steady motion akin to the precision of modern quartz crystals Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.111.
| Hand | Speed (Degrees/Min) | Movement in 1 Hour |
|---|---|---|
| Minute Hand | 6° | 360° |
| Hour Hand | 0.5° | 30° |
| Relative | 5.5° (or 11/2°) | 330° |
Sources: Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.108; Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.111
4. Circular Motion and Tracks (intermediate)
When we move from linear motion to circular motion, the principles of speed and distance remain the same, but the geometry changes. In a linear track, two objects might never meet if they have different speeds and start at different times. However, on a circular track, objects are bound to meet repeatedly because the track "recycles" itself. As we see in basic physics, uniform motion occurs when an object covers equal distances in equal intervals of time Science-Class VII, Measurement of Time and Motion, p.117. In the context of a circular track or a clock, this distance is often measured in degrees (°) rather than meters.
One of the most common applications of circular motion in aptitude tests is the Clock Face. Think of a clock as a circular track of 360°. The "runners" are the hands of the clock, each moving at a constant (uniform) speed. To master these problems, you must internalize the angular speeds of the hands:
| Hand | Total Distance / Time | Angular Speed |
|---|---|---|
| Minute Hand | 360° in 60 minutes | 6° per minute |
| Hour Hand | 30° in 60 minutes (1 hour) | 0.5° per minute |
The Relative Speed between the minute hand and the hour hand is crucial. Since they move in the same direction, we subtract their speeds: 6° - 0.5° = 5.5° per minute. This relative speed tells us how quickly the minute hand "gains" on the hour hand. Whether you are calculating the angle between hands at 9:14 or determining when they will next coincide, this 5.5° constant is your most powerful tool.
In more complex circular track problems involving runners, the Time of Meeting is calculated by dividing the total length of the track by the Relative Speed. If two runners move in opposite directions, you add their speeds; if they move in the same direction, you subtract them. Just as linear settlements develop along a straight path Geography of India, Settlements, p.7, circular motion problems require you to visualize the "loop" where the end meets the beginning, making the relative distance effectively the length of the track.
Sources: Science-Class VII, Measurement of Time and Motion, p.117; Geography of India, Settlements, p.7
5. Faulty Clocks: Gaining and Losing Time (exam-level)
To master the concept of Faulty Clocks, we must first understand the fundamental mechanics of a standard clock. All time-keeping devices, from historical pendulum clocks to modern quartz versions, rely on periodic motion—processes that repeat at regular intervals (Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.111). In a standard 12-hour clock, the Minute Hand moves 360° in 60 minutes (6° per minute), while the Hour Hand moves 360° in 12 hours, which translates to 30° per hour or 0.5° per minute. A clock is considered 'faulty' when it either gains time (runs faster than it should) or loses time (runs slower than it should). For instance, while a perfect atomic clock might lose only one second in millions of years, early mechanical clocks could lose or gain up to 10 seconds a day (Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.111).When solving UPSC-level problems involving faulty clocks, the key is to establish a ratio of consistency between 'Clock Time' and 'True Time.' If a clock gains 5 minutes every hour, it means that for every 60 minutes of real time, the faulty clock displays 65 minutes. To find the correct time when the faulty clock shows a certain duration, we use the formula:
Correct Time Intervals = (True Time / Faulty Time) × Total Time shown by the faulty clock.
This relative comparison is vital because standard time across the globe is calculated relative to Greenwich Mean Time (GMT), where longitudes determine if a region is ahead or behind in time (Physical Geography by PMF IAS, Latitudes and Longitudes, p.244).
Another sophisticated variation involves the interchange of hands. At any given moment, the exact position of the hands is determined by their angular velocity. For example, at 9:14, the hour hand has moved 277° from the 12 o'clock position (30° × 9 + 0.5° × 14), and the minute hand is at 84° (6° × 14). If the positions are interchanged, the new minute-hand angle (277°) and hour-hand angle (84°) would indicate a completely different time, often used in puzzles to test a student's grasp of angular displacement. Understanding these smallest intervals—even down to the second—is the basis for all precision measurement (Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.112).
| Clock Condition | Description | Mathematical Impact |
|---|---|---|
| Gaining Time | The clock runs fast. | Clock Time > True Time |
| Losing Time | The clock runs slow. | Clock Time < True Time |
| Interchanged Hands | Positions of H and M hands swap. | Angles (θ) are swapped; minutes = θ_hour / 6 |
Sources: Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.111; Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.112; Physical Geography by PMF IAS, Latitudes and Longitudes, p.244
6. Angle Calculation Formula (intermediate)
To master clock-based quantitative problems, we must first view the clock face not just as a time-teller, but as a geometric circle of 360°. While ancient methods like shadow sticks and sinking bowl water clocks were used to track time in India Science-Class VII, Measurement of Time and Motion, p.108, modern analog clocks rely on the precise angular velocity of their hands. Understanding how to calculate the angle between these hands is essential for solving complex arrangement and interchange problems.
The calculation is based on the relative speeds of the two hands. We define their positions in degrees, measured clockwise from the 12 o'clock position (which we treat as 0°):
- Minute Hand: It completes 360° in 60 minutes. Therefore, its speed is 6° per minute (360/60).
- Hour Hand: It completes 360° in 12 hours. This means it moves 30° every hour (360/12). However, it doesn't stay still while the minute hand moves; it also crawls forward at a rate of 0.5° per minute (30°/60 min).
To find the angle between the hands at any time H:M, we use the formula: Angle (θ) = |30H - (11/2)M|. Here, H represents the hours and M represents the minutes. The term 11/2 (or 5.5) comes from subtracting the hour hand's minute-drift (0.5°) from the minute hand's speed (6°). Just as we measure the angle of elevation for geographic positioning Certificate Physical and Human Geography, The Earth's Crust, p.9, calculating this "angle of deviation" between the hands allows us to pinpoint the exact state of the clock at any given second Science-Class VII, Measurement of Time and Motion, p.112.
| Hand Type | Angular Speed | Movement in 10 Minutes |
|---|---|---|
| Minute Hand | 6° / minute | 60° |
| Hour Hand | 0.5° / minute | 5° |
Sources: Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.108; Science-Class VII . NCERT(Revised ed 2025), Measurement of Time and Motion, p.112; Certificate Physical and Human Geography , GC Leong (Oxford University press 3rd ed.), The Earth's Crust, p.9
7. Determining Position via Angular Displacement (exam-level)
To master position-based problems, we must first understand that both the Earth and a clock are circular systems where time is a function of angular displacement. Just as the Earth rotates 360° in 24 hours, meaning it passes through 15° every hour or 1° every 4 minutes Certificate Physical and Human Geography (GC Leong), The Earth's Crust, p.11, the hands of a clock move at specific angular speeds to indicate the 'position' of time. In the UPSC CSAT or Geography papers, you will often need to convert these 'angles' into 'positions' (like longitude or exact minutes) and vice versa. To calculate any position on a clock face, we use the 12 o'clock mark as our 0° reference. The two hands move at different rates, creating a dynamic relationship:| Hand | Angular Speed per Hour | Angular Speed per Minute |
|---|---|---|
| Minute Hand | 360° | 6° (since 360°/60 min) |
| Hour Hand | 30° (since 360°/12 hr) | 0.5° (since 30°/60 min) |
Sources: Certificate Physical and Human Geography (GC Leong), The Earth's Crust, p.11; INDIA PHYSICAL ENVIRONMENT (NCERT Class XI), India — Location, p.2; Physical Geography (PMF IAS), Latitudes and Longitudes, p.243
8. Solving the Hand Interchange Problem (exam-level)
In quantitative aptitude, the Hand Interchange Problem is a classic test of your ability to map physical space (degrees) to time. Just as modern clocks use periodic vibrations to mark equal intervals Science-Class VII . NCERT, Measurement of Time and Motion, p.111, we must view the clock face as a 360° circle where two hands move at different, yet constant, speeds.
To solve these, we first establish the angular speed of each hand:
- Minute Hand: It completes 360° in 60 minutes. Therefore, its speed is 360/60 = 6° per minute.
- Hour Hand: It completes 360° in 12 hours (720 minutes). Its speed is 360/12 = 30° per hour, which breaks down further to 30/60 = 0.5° per minute.
When a problem states that hands are "interchanged," it means the physical position (the angle) of the original hour hand becomes the new position of the minute hand, and vice-versa. This is very similar to how we calculate local time based on longitude, where a 1° change in position equals a 4-minute change in time Certificate Physical and Human Geography , GC Leong, The Earth's Crust, p.11. In a clock, however, we must account for the total degrees from the 12 o'clock mark.
| Step | Calculation Logic |
|---|---|
| 1. Find Initial Angles | Minute angle = Minutes × 6°. Hour angle = (Hours × 30°) + (Minutes × 0.5°). |
| 2. Swap Positions | New Minute Position = Old Hour Angle. New Hour Position = Old Minute Angle. |
| 3. Convert Back to Time | New Minutes = New Minute Position / 6. New Hour = New Hour Position / 30. |
For example, if a clock shows 9:14, the minute hand is at 84° (14 × 6) and the hour hand is at 277° (9 × 30 + 14 × 0.5). If they interchange, the new minute hand is now at 277°. To find the new time, we divide 277 by 6, giving us approximately 46.16 minutes. Since the new hour hand is now at 84°, and 84/30 is roughly 2.8, we know the new time is approximately 2:46.
Sources: Science-Class VII . NCERT, Measurement of Time and Motion, p.111; Certificate Physical and Human Geography , GC Leong, The Earth's Crust, p.11; Physical Geography by PMF IAS, Latitudes and Longitudes, p.243
9. Solving the Original PYQ (exam-level)
Now that you have mastered angular displacement and the relative speed of clock hands, this PYQ serves as the ultimate test of your precision. To solve this, you must synthesize the fundamental building blocks you just learned: the minute hand moves at 6° per minute, while the hour hand moves at 0.5° per minute. By converting the time 9:14 into specific degrees, you transition from a simple visual observation to the exact mathematical positioning required for UPSC CSAT problems.
Let’s walk through the coach’s logic: At 9:14, the minute hand is at 84° (14 min × 6°). The hour hand has moved 270° to reach the 9 o’clock mark plus an additional 7° due to the 14 minutes passed (14 × 0.5°), totaling 277°. When these positions are exactly interchanged, the new minute hand is at 277°. Dividing 277 by 6 gives us approximately 46.16 minutes. Simultaneously, the hour hand at 84° indicates the time is between 2 and 3 o’clock. As 46 minutes past 2 is equivalent to 14 minutes before 3, we arrive at the correct answer: Fourteen minutes to three.
UPSC frequently uses close-interval options (12, 13, 14, and 15 minutes) as a trap for students who rely on visual estimation rather than calculation. A common mistake is to assume the hand at "9" simply moves to "roughly 45 minutes" (Option D), forgetting that the hour hand had progressed 7° past the 9. Always remember: in an exact interchange, even the smallest degree counts. Precision is the difference between a calculated success and a common trap. You can find more practice on these mechanics in Analytical Reasoning by M.K. Pandey.
SIMILAR QUESTIONS
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An accurate clock shows the time as 3.00. After hour hand has moved 135°, the time would be
The number of times the hands of a watch are at right angle between 4 p.m. to 10 p.m. is :
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5 Cross-Linked PYQs Behind This Question
UPSC repeats concepts across years. See how this question connects to 5 others — spot the pattern.
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