The square root of the cube of this number is the cube of its square root. It is not 1 and it is less than 6. What is it ?

The question describes a mathematical identity. Let the number be x. The two conditions given are:

• Square root of the cube: √(x³) = (x³)^{1/2} = x^{3/2}
• Cube of the square root: (√x)³ = (x^{1/2})³ = x^{3/2}

Mathematically, x^{3/2} = x^{3/2} is an identity that holds true for all non-negative numbers. However, the problem provides specific constraints: the number is not 1 and is less than 6. Among the options (2, 3, 4, 5), all satisfy the mathematical condition. In competitive exams, 4 is the intended answer because it is the only perfect square, allowing the square root to result in a rational integer (√4 = 2), making the calculation clean (8 = 8).