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The equivalent weight of Ba(OH)2 is (given, atomic weight of Ba is 137-3)
Explanation
The equivalent weight of a base is calculated by dividing its molar mass by its acidity (the number of replaceable hydroxide ions) [1]. Barium hydroxide, Ba(OH)2, is a strong base that dissociates to produce two hydroxide (OH–) ions per molecule [1]. To find the molar mass, we sum the atomic weights: Ba (137.3) + 2 × [O (16.0) + H (1.0)], which equals 171.3 g/mol. Since the acidity of Ba(OH)2 is 2, the equivalent weight is determined by the formula: Molar Mass / Acidity [1]. Substituting the values, we get 171.3 / 2 = 85.65. Among the given options, 85.7 (rounded) is the correct value. This calculation follows the standard chemical principle where one equivalent weight is the mass that yields one mole of hydroxide ions.
Sources
- [1] https://mlsu.ac.in/econtents/1844_SPOT%20I.pdf